What are the solutions to the equation 4n^2+6n-9=0 ?

The solutions to the equation 4n^2+6n-9=0 are n=(3(sqrt(5)-1))/4 ,n=-(3(1+sqrt(5)))/4

Find the zeros of 4n^2+6n-9=0

The zeros of 4n^2+6n-9=0 are n=(3(sqrt(5)-1))/4 ,n=-(3(1+sqrt(5)))/4

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4 n^{2} + 6 n - 9 = 0

n = \frac{3 ( 5 - 1 )}{4}, n = - \frac{3 ( 1 + 5 )}{4}

Solution steps

4 n^{2} + 6 n - 9 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 4 ( - 9 )}{2 \cdot 4}

6^{2} - 4 \cdot 4 (- 9) = 65

n_{1, 2} = \frac{- 6 \pm 6 5}{2 \cdot 4}

Separate the solutions

n_{1} = \frac{- 6 + 6 5}{2 \cdot 4}, n_{2} = \frac{- 6 - 6 5}{2 \cdot 4}

n = \frac{- 6 + 6 5}{2 \cdot 4} : \frac{3 ( 5 - 1 )}{4}

n = \frac{- 6 - 6 5}{2 \cdot 4} : - \frac{3 ( 1 + 5 )}{4}

The solutions to the quadratic equation are:

n = \frac{3 ( 5 - 1 )}{4}, n = - \frac{3 ( 1 + 5 )}{4}

x^{2} - 2 x = - 26

x^{2} + (- 3) x + 2 = 0

5 t^{2} - 5 t - 30 = 0

(x + 1) (x - 3) = 2 (x + 5) - 16

9 m^{2} = 5 m^{2} - 10

What are the solutions to the equation 4n^2+6n-9=0 ?
The solutions to the equation 4n^2+6n-9=0 are n=(3(sqrt(5)-1))/4 ,n=-(3(1+sqrt(5)))/4
Find the zeros of 4n^2+6n-9=0
The zeros of 4n^2+6n-9=0 are n=(3(sqrt(5)-1))/4 ,n=-(3(1+sqrt(5)))/4