What are the solutions to the equation 5t^2-5t-30=0 ?

The solutions to the equation 5t^2-5t-30=0 are t=3,t=-2

Find the zeros of 5t^2-5t-30=0

The zeros of 5t^2-5t-30=0 are t=3,t=-2

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5 t^{2} - 5 t - 30 = 0

t = 3, t = - 2

Solution steps

5 t^{2} - 5 t - 30 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 5 ( - 30 )}{2 \cdot 5}

(- 5)^{2} - 4 \cdot 5 (- 30) = 25

t_{1, 2} = \frac{- ( - 5 ) \pm 25}{2 \cdot 5}

Separate the solutions

t_{1} = \frac{- ( - 5 ) + 25}{2 \cdot 5}, t_{2} = \frac{- ( - 5 ) - 25}{2 \cdot 5}

t = \frac{- ( - 5 ) + 25}{2 \cdot 5} : 3

t = \frac{- ( - 5 ) - 25}{2 \cdot 5} : - 2

The solutions to the quadratic equation are:

t = 3, t = - 2

(x + 1) (x - 3) = 2 (x + 5) - 16

9 m^{2} = 5 m^{2} - 10

3 x^{2} - 7 x - 12 = 0

(x - 5) (x + 2) = - 6

8 + 4 x - x^{2} = 0

What are the solutions to the equation 5t^2-5t-30=0 ?
The solutions to the equation 5t^2-5t-30=0 are t=3,t=-2
Find the zeros of 5t^2-5t-30=0
The zeros of 5t^2-5t-30=0 are t=3,t=-2