What are the solutions to the equation 3x^2-7x-12=0 ?

The solutions to the equation 3x^2-7x-12=0 are x=(7+sqrt(193))/6 ,x=(7-sqrt(193))/6

Find the zeros of 3x^2-7x-12=0

The zeros of 3x^2-7x-12=0 are x=(7+sqrt(193))/6 ,x=(7-sqrt(193))/6

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3 x^{2} - 7 x - 12 = 0

x = \frac{7 + 193}{6}, x = \frac{7 - 193}{6}

Solution steps

3 x^{2} - 7 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 ( - 12 )}{2 \cdot 3}

(- 7)^{2} - 4 \cdot 3 (- 12) = 193

x_{1, 2} = \frac{- ( - 7 ) \pm 193}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 193}{2 \cdot 3}, x_{2} = \frac{- ( - 7 ) - 193}{2 \cdot 3}

x = \frac{- ( - 7 ) + 193}{2 \cdot 3} : \frac{7 + 193}{6}

x = \frac{- ( - 7 ) - 193}{2 \cdot 3} : \frac{7 - 193}{6}

The solutions to the quadratic equation are:

x = \frac{7 + 193}{6}, x = \frac{7 - 193}{6}

(x - 5) (x + 2) = - 6

8 + 4 x - x^{2} = 0

2 x (x - 3) = 1

5 (p^{2} - 4) - 1 = 4

- 4 x^{2} + 8 x = 7

What are the solutions to the equation 3x^2-7x-12=0 ?
The solutions to the equation 3x^2-7x-12=0 are x=(7+sqrt(193))/6 ,x=(7-sqrt(193))/6
Find the zeros of 3x^2-7x-12=0
The zeros of 3x^2-7x-12=0 are x=(7+sqrt(193))/6 ,x=(7-sqrt(193))/6