What are the solutions to the equation r^2-8r+9=0 ?

The solutions to the equation r^2-8r+9=0 are r=4+sqrt(7),r=4-sqrt(7)

Find the zeros of r^2-8r+9=0

The zeros of r^2-8r+9=0 are r=4+sqrt(7),r=4-sqrt(7)

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r^{2} - 8 r + 9 = 0

r = 4 + 7, r = 4 - 7

Solution steps

r^{2} - 8 r + 9 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 9 = 27

r_{1, 2} = \frac{- ( - 8 ) \pm 2 7}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 8 ) + 2 7}{2 \cdot 1}, r_{2} = \frac{- ( - 8 ) - 2 7}{2 \cdot 1}

r = \frac{- ( - 8 ) + 2 7}{2 \cdot 1} : 4 + 7

r = \frac{- ( - 8 ) - 2 7}{2 \cdot 1} : 4 - 7

The solutions to the quadratic equation are:

r = 4 + 7, r = 4 - 7

8 \cdot 5

1 - \frac{2}{3} \times \frac{2}{3}

(\frac{36}{49})^{\frac{3}{2}}

u^{2} = 13 u

x 3 = 3

What are the solutions to the equation r^2-8r+9=0 ?
The solutions to the equation r^2-8r+9=0 are r=4+sqrt(7),r=4-sqrt(7)
Find the zeros of r^2-8r+9=0
The zeros of r^2-8r+9=0 are r=4+sqrt(7),r=4-sqrt(7)