What are the solutions to the equation -4x^2+8x=7 ?

The solutions to the equation -4x^2+8x=7 are x=1-i(sqrt(3))/2 ,x=1+i(sqrt(3))/2

Find the zeros of -4x^2+8x=7

The zeros of -4x^2+8x=7 are x=1-i(sqrt(3))/2 ,x=1+i(sqrt(3))/2

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- 4 x^{2} + 8 x = 7

x = 1 - i \frac{3}{2}, x = 1 + i \frac{3}{2}

Solution steps

- 4 x^{2} + 8 x = 7

Move

7

to the left side

- 4 x^{2} + 8 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 4 ) ( - 7 )}{2 ( - 4 )}

Simplify

8^{2} - 4 (- 4) (- 7) : 43 i

x_{1, 2} = \frac{- 8 \pm 4 3 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 8 + 4 3 i}{2 ( - 4 )}, x_{2} = \frac{- 8 - 4 3 i}{2 ( - 4 )}

x = \frac{- 8 + 4 3 i}{2 ( - 4 )} : 1 - i \frac{3}{2}

x = \frac{- 8 - 4 3 i}{2 ( - 4 )} : 1 + i \frac{3}{2}

The solutions to the quadratic equation are:

x = 1 - i \frac{3}{2}, x = 1 + i \frac{3}{2}

3 - 2 x^{2} = - 5

\frac{7}{5} x^{2} = 2

y^{2} - 12 y = - 25

x^{2} - 35 x = 60

3 s^{2} - 22 s = 16

What are the solutions to the equation -4x^2+8x=7 ?
The solutions to the equation -4x^2+8x=7 are x=1-i(sqrt(3))/2 ,x=1+i(sqrt(3))/2
Find the zeros of -4x^2+8x=7
The zeros of -4x^2+8x=7 are x=1-i(sqrt(3))/2 ,x=1+i(sqrt(3))/2