What are the solutions to the equation (2/3)x^2+5x-9=0 ?

The solutions to the equation (2/3)x^2+5x-9=0 are x= 3/2 ,x=-9

Find the zeros of (2/3)x^2+5x-9=0

The zeros of (2/3)x^2+5x-9=0 are x= 3/2 ,x=-9

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(\frac{2}{3}) x^{2} + 5 x - 9 = 0

x = \frac{3}{2}, x = - 9

Decimal Notation

x = 1.5, x = - 9

Solution steps

(\frac{2}{3}) x^{2} + 5 x - 9 = 0

Refine

\frac{2}{3} x^{2} + 5 x - 9 = 0

Write in the standard form

a x^{2} + b x + c = 0

\frac{2 x ^{2}}{3} + 5 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot \frac{2}{3} ( - 9 )}{2 \cdot \frac{2}{3}}

5^{2} - 4 \cdot \frac{2}{3} (- 9) = 7

x_{1, 2} = \frac{- 5 \pm 7}{2 \cdot \frac{2}{3}}

Separate the solutions

x_{1} = \frac{- 5 + 7}{2 \cdot \frac{2}{3}}, x_{2} = \frac{- 5 - 7}{2 \cdot \frac{2}{3}}

x = \frac{- 5 + 7}{2 \frac{2}{3}} : \frac{3}{2}

x = \frac{- 5 - 7}{2 \frac{2}{3}} : - 9

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - 9

r^{2} + 10 r - 18 = 61

h^{2} - 4 h - 32 = 0

G (x) = x^{2} + 2

y^{2} - 4 y + 9 = 0

y^{2} - 144 = 0

What are the solutions to the equation (2/3)x^2+5x-9=0 ?
The solutions to the equation (2/3)x^2+5x-9=0 are x= 3/2 ,x=-9
Find the zeros of (2/3)x^2+5x-9=0
The zeros of (2/3)x^2+5x-9=0 are x= 3/2 ,x=-9