What are the solutions to the equation y^2-4y+9=0 ?

The solutions to the equation y^2-4y+9=0 are y=2+sqrt(5)i,y=2-sqrt(5)i

Find the zeros of y^2-4y+9=0

The zeros of y^2-4y+9=0 are y=2+sqrt(5)i,y=2-sqrt(5)i

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y^{2} - 4 y + 9 = 0

y = 2 + 5 i, y = 2 - 5 i

Solution steps

y^{2} - 4 y + 9 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 9 : 25 i

y_{1, 2} = \frac{- ( - 4 ) \pm 2 5 i}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 4 ) + 2 5 i}{2 \cdot 1}, y_{2} = \frac{- ( - 4 ) - 2 5 i}{2 \cdot 1}

y = \frac{- ( - 4 ) + 2 5 i}{2 \cdot 1} : 2 + 5 i

y = \frac{- ( - 4 ) - 2 5 i}{2 \cdot 1} : 2 - 5 i

The solutions to the quadratic equation are:

y = 2 + 5 i, y = 2 - 5 i

y^{2} - 144 = 0

14 y^{2} - 3 = - 19 y

x^{2} = 2 x

3 z^{2} + 10 z = - 8

- 45 (3 - 15 x)^{2} = - 5

What are the solutions to the equation y^2-4y+9=0 ?
The solutions to the equation y^2-4y+9=0 are y=2+sqrt(5)i,y=2-sqrt(5)i
Find the zeros of y^2-4y+9=0
The zeros of y^2-4y+9=0 are y=2+sqrt(5)i,y=2-sqrt(5)i