What are the solutions to the equation 3z^2+10z=-8 ?

The solutions to the equation 3z^2+10z=-8 are z=-4/3 ,z=-2

Find the zeros of 3z^2+10z=-8

The zeros of 3z^2+10z=-8 are z=-4/3 ,z=-2

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3 z^{2} + 10 z = - 8

z = - \frac{4}{3}, z = - 2

Decimal Notation

z = - 1.33333 \dots, z = - 2

Solution steps

3 z^{2} + 10 z = - 8

Move

8

to the left side

3 z^{2} + 10 z + 8 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 \cdot 8}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 \cdot 8 = 2

z_{1, 2} = \frac{- 10 \pm 2}{2 \cdot 3}

Separate the solutions

z_{1} = \frac{- 10 + 2}{2 \cdot 3}, z_{2} = \frac{- 10 - 2}{2 \cdot 3}

z = \frac{- 10 + 2}{2 \cdot 3} : - \frac{4}{3}

z = \frac{- 10 - 2}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

z = - \frac{4}{3}, z = - 2

- 45 (3 - 15 x)^{2} = - 5

p^{2} + n p - 4 = 0

(x + 19)^{2} = - 4

r, a = 4 π r^{2}

x^{2} + 4 x + 12

What are the solutions to the equation 3z^2+10z=-8 ?
The solutions to the equation 3z^2+10z=-8 are z=-4/3 ,z=-2
Find the zeros of 3z^2+10z=-8
The zeros of 3z^2+10z=-8 are z=-4/3 ,z=-2