What are the solutions to the equation (x+19)^2=-4 ?

The solutions to the equation (x+19)^2=-4 are x=2i-19,x=-2i-19

Find the zeros of (x+19)^2=-4

The zeros of (x+19)^2=-4 are x=2i-19,x=-2i-19

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(x + 19)^{2} = - 4

x = 2 i - 19, x = - 2 i - 19

Solution steps

(x + 19)^{2} = - 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 19 = - 4 : x = 2 i - 19

Solve

x + 19 = - - 4 : x = - 2 i - 19

The solutions to the quadratic equation are:

x = 2 i - 19, x = - 2 i - 19

r, a = 4 π r^{2}

x^{2} + 4 x + 12

z^{2} - 0.3063 z + 0.4317 = 0

2 x^{2} + 2 x - 10 = 0

c^{2} + c = 2

What are the solutions to the equation (x+19)^2=-4 ?
The solutions to the equation (x+19)^2=-4 are x=2i-19,x=-2i-19
Find the zeros of (x+19)^2=-4
The zeros of (x+19)^2=-4 are x=2i-19,x=-2i-19