What are the solutions to the equation 2x^2+2x-10=0 ?

The solutions to the equation 2x^2+2x-10=0 are x=(-1+sqrt(21))/2 ,x=-(1+sqrt(21))/2

Find the zeros of 2x^2+2x-10=0

The zeros of 2x^2+2x-10=0 are x=(-1+sqrt(21))/2 ,x=-(1+sqrt(21))/2

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2 x^{2} + 2 x - 10 = 0

x = \frac{- 1 + 21}{2}, x = - \frac{1 + 21}{2}

Decimal Notation

x = 1.79128 \dots, x = - 2.79128 \dots

Solution steps

2 x^{2} + 2 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

2^{2} - 4 \cdot 2 (- 10) = 221

x_{1, 2} = \frac{- 2 \pm 2 21}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 2 + 2 21}{2 \cdot 2}, x_{2} = \frac{- 2 - 2 21}{2 \cdot 2}

x = \frac{- 2 + 2 21}{2 \cdot 2} : \frac{- 1 + 21}{2}

x = \frac{- 2 - 2 21}{2 \cdot 2} : - \frac{1 + 21}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 21}{2}, x = - \frac{1 + 21}{2}

c^{2} + c = 2

(3 - X)^{2} + X^{2} = 2 (5 - X)

8 x^{2} - 20 = 0

\frac{x ^{2}}{2} = x

- 2 x^{2} = - 72

What are the solutions to the equation 2x^2+2x-10=0 ?
The solutions to the equation 2x^2+2x-10=0 are x=(-1+sqrt(21))/2 ,x=-(1+sqrt(21))/2
Find the zeros of 2x^2+2x-10=0
The zeros of 2x^2+2x-10=0 are x=(-1+sqrt(21))/2 ,x=-(1+sqrt(21))/2