What are the solutions to the equation y^2=-16y ?

The solutions to the equation y^2=-16y are y=0,y=-16

Find the zeros of y^2=-16y

The zeros of y^2=-16y are y=0,y=-16

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y^{2} = - 16 y

y = 0, y = - 16

Solution steps

y^{2} = - 16 y

Move

16 y

to the left side

y^{2} + 16 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 0 = 16

y_{1, 2} = \frac{- 16 \pm 16}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 16 + 16}{2 \cdot 1}, y_{2} = \frac{- 16 - 16}{2 \cdot 1}

y = \frac{- 16 + 16}{2 \cdot 1} : 0

y = \frac{- 16 - 16}{2 \cdot 1} : - 16

The solutions to the quadratic equation are:

y = 0, y = - 16

- 4 x^{2} - 2 x + 9 = 0

3 (2 x + 1)^{2} + 2 = 7

w^{2} + 50 = - 15 w

4 x^{2} + 7 x - 7 = 0

3 x^{2} - 5 x + 1

What are the solutions to the equation y^2=-16y ?
The solutions to the equation y^2=-16y are y=0,y=-16
Find the zeros of y^2=-16y
The zeros of y^2=-16y are y=0,y=-16