What are the solutions to the equation n^2+7n=8 ?

The solutions to the equation n^2+7n=8 are n=1,n=-8

Find the zeros of n^2+7n=8

The zeros of n^2+7n=8 are n=1,n=-8

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n^{2} + 7 n = 8

n = 1, n = - 8

Solution steps

n^{2} + 7 n = 8

Move

8

to the left side

n^{2} + 7 n - 8 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 8) = 9

n_{1, 2} = \frac{- 7 \pm 9}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 7 + 9}{2 \cdot 1}, n_{2} = \frac{- 7 - 9}{2 \cdot 1}

n = \frac{- 7 + 9}{2 \cdot 1} : 1

n = \frac{- 7 - 9}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

n = 1, n = - 8

3 x + 2 x^{2} = 5 x^{2} - 6

x^{2} - 3 a x + a^{2} = 0

15 + (x - 4)^{2} = 7

3 (x^{2} - 3) = 35 x + 19

6 v^{2} + 3 = - 2 v

What are the solutions to the equation n^2+7n=8 ?
The solutions to the equation n^2+7n=8 are n=1,n=-8
Find the zeros of n^2+7n=8
The zeros of n^2+7n=8 are n=1,n=-8