What are the solutions to the equation x^2-14x+20=-4 ?

The solutions to the equation x^2-14x+20=-4 are x=12,x=2

Find the zeros of x^2-14x+20=-4

The zeros of x^2-14x+20=-4 are x=12,x=2

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x^{2} - 14 x + 20 = - 4

x = 12, x = 2

Solution steps

x^{2} - 14 x + 20 = - 4

Move

4

to the left side

x^{2} - 14 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 24 = 10

x_{1, 2} = \frac{- ( - 14 ) \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 10}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 10}{2 \cdot 1}

x = \frac{- ( - 14 ) + 10}{2 \cdot 1} : 12

x = \frac{- ( - 14 ) - 10}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 12, x = 2

6 y^{2} - 7 y + 2 = 0

x - (x - 7)^{2} = 1 + x - 6 x^{2}

3 + 2 x - x^{2}

x, 3 x^{2} + k x + 12 = 0

(5 x - 1)^{2} = 49

What are the solutions to the equation x^2-14x+20=-4 ?
The solutions to the equation x^2-14x+20=-4 are x=12,x=2
Find the zeros of x^2-14x+20=-4
The zeros of x^2-14x+20=-4 are x=12,x=2