What are the solutions to the equation 6y^2-7y+2=0 ?

The solutions to the equation 6y^2-7y+2=0 are y= 2/3 ,y= 1/2

Find the zeros of 6y^2-7y+2=0

The zeros of 6y^2-7y+2=0 are y= 2/3 ,y= 1/2

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6 y^{2} - 7 y + 2 = 0

y = \frac{2}{3}, y = \frac{1}{2}

Decimal Notation

y = 0.66666 \dots, y = 0.5

Solution steps

6 y^{2} - 7 y + 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 6 \cdot 2}{2 \cdot 6}

(- 7)^{2} - 4 \cdot 6 \cdot 2 = 1

y_{1, 2} = \frac{- ( - 7 ) \pm 1}{2 \cdot 6}

Separate the solutions

y_{1} = \frac{- ( - 7 ) + 1}{2 \cdot 6}, y_{2} = \frac{- ( - 7 ) - 1}{2 \cdot 6}

y = \frac{- ( - 7 ) + 1}{2 \cdot 6} : \frac{2}{3}

y = \frac{- ( - 7 ) - 1}{2 \cdot 6} : \frac{1}{2}

The solutions to the quadratic equation are:

y = \frac{2}{3}, y = \frac{1}{2}

x - (x - 7)^{2} = 1 + x - 6 x^{2}

3 + 2 x - x^{2}

x, 3 x^{2} + k x + 12 = 0

(5 x - 1)^{2} = 49

x^{2} + 20 x - 5000 = 0

What are the solutions to the equation 6y^2-7y+2=0 ?
The solutions to the equation 6y^2-7y+2=0 are y= 2/3 ,y= 1/2
Find the zeros of 6y^2-7y+2=0
The zeros of 6y^2-7y+2=0 are y= 2/3 ,y= 1/2