What are the solutions to the equation x^2+20x-5000=0 ?

The solutions to the equation x^2+20x-5000=0 are x=10(sqrt(51)-1),x=-10(1+sqrt(51))

Find the zeros of x^2+20x-5000=0

The zeros of x^2+20x-5000=0 are x=10(sqrt(51)-1),x=-10(1+sqrt(51))

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x^{2} + 20 x - 5000 = 0

x = 10 (51 - 1), x = - 10 (1 + 51)

Decimal Notation

x = 61.41428 \dots, x = - 81.41428 \dots

Solution steps

x^{2} + 20 x - 5000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot ( - 5000 )}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot (- 5000) = 2051

x_{1, 2} = \frac{- 20 \pm 20 51}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 20 51}{2 \cdot 1}, x_{2} = \frac{- 20 - 20 51}{2 \cdot 1}

x = \frac{- 20 + 20 51}{2 \cdot 1} : 10 (51 - 1)

x = \frac{- 20 - 20 51}{2 \cdot 1} : - 10 (1 + 51)

The solutions to the quadratic equation are:

x = 10 (51 - 1), x = - 10 (1 + 51)

(m + 8) (m - 9) = - 16

8 x^{2} - 16 x + 3

y^{2} - 8 y + 22 = 0

(x + 3) (x - 2) = 1

x^{2} + 10 x = 3

What are the solutions to the equation x^2+20x-5000=0 ?
The solutions to the equation x^2+20x-5000=0 are x=10(sqrt(51)-1),x=-10(1+sqrt(51))
Find the zeros of x^2+20x-5000=0
The zeros of x^2+20x-5000=0 are x=10(sqrt(51)-1),x=-10(1+sqrt(51))