What are the solutions to the equation 5x^2+6x-34=0 ?

The solutions to the equation 5x^2+6x-34=0 are x=(-3+sqrt(179))/5 ,x=-(3+sqrt(179))/5

Find the zeros of 5x^2+6x-34=0

The zeros of 5x^2+6x-34=0 are x=(-3+sqrt(179))/5 ,x=-(3+sqrt(179))/5

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5 x^{2} + 6 x - 34 = 0

x = \frac{- 3 + 179}{5}, x = - \frac{3 + 179}{5}

Decimal Notation

x = 2.07581 \dots, x = - 3.27581 \dots

Solution steps

5 x^{2} + 6 x - 34 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 5 ( - 34 )}{2 \cdot 5}

6^{2} - 4 \cdot 5 (- 34) = 2179

x_{1, 2} = \frac{- 6 \pm 2 179}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 6 + 2 179}{2 \cdot 5}, x_{2} = \frac{- 6 - 2 179}{2 \cdot 5}

x = \frac{- 6 + 2 179}{2 \cdot 5} : \frac{- 3 + 179}{5}

x = \frac{- 6 - 2 179}{2 \cdot 5} : - \frac{3 + 179}{5}

The solutions to the quadratic equation are:

x = \frac{- 3 + 179}{5}, x = - \frac{3 + 179}{5}

4 x^{2} + 4 x = 7

5 + 2 x^{2} = 6

5 (x + 2)^{2} - 8 = 72

0 = 2 x^{2} - 3

- 4 y^{2} - 9 y - 3 = 0

What are the solutions to the equation 5x^2+6x-34=0 ?
The solutions to the equation 5x^2+6x-34=0 are x=(-3+sqrt(179))/5 ,x=-(3+sqrt(179))/5
Find the zeros of 5x^2+6x-34=0
The zeros of 5x^2+6x-34=0 are x=(-3+sqrt(179))/5 ,x=-(3+sqrt(179))/5