What are the solutions to the equation 4x^2+4x=7 ?

The solutions to the equation 4x^2+4x=7 are x=(-1+2sqrt(2))/2 ,x=-(1+2sqrt(2))/2

Find the zeros of 4x^2+4x=7

The zeros of 4x^2+4x=7 are x=(-1+2sqrt(2))/2 ,x=-(1+2sqrt(2))/2

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4 x^{2} + 4 x = 7

x = \frac{- 1 + 2 2}{2}, x = - \frac{1 + 2 2}{2}

Decimal Notation

x = 0.91421 \dots, x = - 1.91421 \dots

Solution steps

4 x^{2} + 4 x = 7

Move

7

to the left side

4 x^{2} + 4 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 ( - 7 )}{2 \cdot 4}

4^{2} - 4 \cdot 4 (- 7) = 82

x_{1, 2} = \frac{- 4 \pm 8 2}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 4 + 8 2}{2 \cdot 4}, x_{2} = \frac{- 4 - 8 2}{2 \cdot 4}

x = \frac{- 4 + 8 2}{2 \cdot 4} : \frac{- 1 + 2 2}{2}

x = \frac{- 4 - 8 2}{2 \cdot 4} : - \frac{1 + 2 2}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 2 2}{2}, x = - \frac{1 + 2 2}{2}

5 + 2 x^{2} = 6

5 (x + 2)^{2} - 8 = 72

0 = 2 x^{2} - 3

- 4 y^{2} - 9 y - 3 = 0

x^{2} + 15 x = x + 98

What are the solutions to the equation 4x^2+4x=7 ?
The solutions to the equation 4x^2+4x=7 are x=(-1+2sqrt(2))/2 ,x=-(1+2sqrt(2))/2
Find the zeros of 4x^2+4x=7
The zeros of 4x^2+4x=7 are x=(-1+2sqrt(2))/2 ,x=-(1+2sqrt(2))/2