What are the solutions to the equation c^2-7c+3=-2c ?

The solutions to the equation c^2-7c+3=-2c are c=(5+sqrt(13))/2 ,c=(5-sqrt(13))/2

Find the zeros of c^2-7c+3=-2c

The zeros of c^2-7c+3=-2c are c=(5+sqrt(13))/2 ,c=(5-sqrt(13))/2

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c^{2} - 7 c + 3 = - 2 c

c = \frac{5 + 13}{2}, c = \frac{5 - 13}{2}

Decimal Notation

c = 4.30277 \dots, c = 0.69722 \dots

Solution steps

c^{2} - 7 c + 3 = - 2 c

Move

2 c

to the left side

c^{2} - 5 c + 3 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 3 = 13

c_{1, 2} = \frac{- ( - 5 ) \pm 13}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- ( - 5 ) + 13}{2 \cdot 1}, c_{2} = \frac{- ( - 5 ) - 13}{2 \cdot 1}

c = \frac{- ( - 5 ) + 13}{2 \cdot 1} : \frac{5 + 13}{2}

c = \frac{- ( - 5 ) - 13}{2 \cdot 1} : \frac{5 - 13}{2}

The solutions to the quadratic equation are:

c = \frac{5 + 13}{2}, c = \frac{5 - 13}{2}

2^{2} + x^{2} = 1 0^{2}

x^{2} + 2 x + 30 = 0

0.15 x^{2} - 0.32 x - 3.6 = 0

12 x^{2} - 8 x = 14

(x + 3) (x - 5) = 1

What are the solutions to the equation c^2-7c+3=-2c ?
The solutions to the equation c^2-7c+3=-2c are c=(5+sqrt(13))/2 ,c=(5-sqrt(13))/2
Find the zeros of c^2-7c+3=-2c
The zeros of c^2-7c+3=-2c are c=(5+sqrt(13))/2 ,c=(5-sqrt(13))/2