What are the solutions to the equation 12x^2-8x=14 ?

The solutions to the equation 12x^2-8x=14 are x=(2+sqrt(46))/6 ,x=(2-sqrt(46))/6

Find the zeros of 12x^2-8x=14

The zeros of 12x^2-8x=14 are x=(2+sqrt(46))/6 ,x=(2-sqrt(46))/6

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12 x^{2} - 8 x = 14

x = \frac{2 + 46}{6}, x = \frac{2 - 46}{6}

Decimal Notation

x = 1.46372 \dots, x = - 0.79705 \dots

Solution steps

12 x^{2} - 8 x = 14

Move

14

to the left side

12 x^{2} - 8 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 12 ( - 14 )}{2 \cdot 12}

(- 8)^{2} - 4 \cdot 12 (- 14) = 446

x_{1, 2} = \frac{- ( - 8 ) \pm 4 46}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 46}{2 \cdot 12}, x_{2} = \frac{- ( - 8 ) - 4 46}{2 \cdot 12}

x = \frac{- ( - 8 ) + 4 46}{2 \cdot 12} : \frac{2 + 46}{6}

x = \frac{- ( - 8 ) - 4 46}{2 \cdot 12} : \frac{2 - 46}{6}

The solutions to the quadratic equation are:

x = \frac{2 + 46}{6}, x = \frac{2 - 46}{6}

(x + 3) (x - 5) = 1

2 (3 k - 1)^{2} = 18

- 3 x^{2} + 6 x = - 1

(- 2)^{3} = (- 2) x (- 2) x (- 2)

4 s^{2} + 4 s + 5 = 0

What are the solutions to the equation 12x^2-8x=14 ?
The solutions to the equation 12x^2-8x=14 are x=(2+sqrt(46))/6 ,x=(2-sqrt(46))/6
Find the zeros of 12x^2-8x=14
The zeros of 12x^2-8x=14 are x=(2+sqrt(46))/6 ,x=(2-sqrt(46))/6