What are the solutions to the equation 0=-2.7t^2+30t+6.5 ?

The solutions to the equation 0=-2.7t^2+30t+6.5 are t=-(-50+7sqrt(55))/9 ,t=(50+7sqrt(55))/9

Find the zeros of 0=-2.7t^2+30t+6.5

The zeros of 0=-2.7t^2+30t+6.5 are t=-(-50+7sqrt(55))/9 ,t=(50+7sqrt(55))/9

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0 = - 2.7 t^{2} + 30 t + 6.5

t = - \frac{- 50 + 7 55}{9}, t = \frac{50 + 7 55}{9}

Decimal Notation

t = - 0.21259 \dots, t = 11.32370 \dots

Solution steps

0 = - 2.7 t^{2} + 30 t + 6.5

Multiply both sides by

10

0 = - 27 t^{2} + 300 t + 65

Switch sides

- 27 t^{2} + 300 t + 65 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 300 \pm 30 0 ^{2} - 4 ( - 27 ) \cdot 65}{2 ( - 27 )}

30 0^{2} - 4 (- 27) \cdot 65 = 4255

t_{1, 2} = \frac{- 300 \pm 42 55}{2 ( - 27 )}

Separate the solutions

t_{1} = \frac{- 300 + 42 55}{2 ( - 27 )}, t_{2} = \frac{- 300 - 42 55}{2 ( - 27 )}

t = \frac{- 300 + 42 55}{2 ( - 27 )} : - \frac{- 50 + 7 55}{9}

t = \frac{- 300 - 42 55}{2 ( - 27 )} : \frac{50 + 7 55}{9}

The solutions to the quadratic equation are:

t = - \frac{- 50 + 7 55}{9}, t = \frac{50 + 7 55}{9}

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- 3 x^{2} - 48 x = 0

- 2 x^{2} + 7 x + 15 = 0

What are the solutions to the equation 0=-2.7t^2+30t+6.5 ?
The solutions to the equation 0=-2.7t^2+30t+6.5 are t=-(-50+7sqrt(55))/9 ,t=(50+7sqrt(55))/9
Find the zeros of 0=-2.7t^2+30t+6.5
The zeros of 0=-2.7t^2+30t+6.5 are t=-(-50+7sqrt(55))/9 ,t=(50+7sqrt(55))/9