What are the solutions to the equation 6x^2+23x=-7 ?

The solutions to the equation 6x^2+23x=-7 are x=-1/3 ,x=-7/2

Find the zeros of 6x^2+23x=-7

The zeros of 6x^2+23x=-7 are x=-1/3 ,x=-7/2

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6 x^{2} + 23 x = - 7

x = - \frac{1}{3}, x = - \frac{7}{2}

Decimal Notation

x = - 0.33333 \dots, x = - 3.5

Solution steps

6 x^{2} + 23 x = - 7

Move

7

to the left side

6 x^{2} + 23 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 23 \pm 2 3 ^{2} - 4 \cdot 6 \cdot 7}{2 \cdot 6}

2 3^{2} - 4 \cdot 6 \cdot 7 = 19

x_{1, 2} = \frac{- 23 \pm 19}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 23 + 19}{2 \cdot 6}, x_{2} = \frac{- 23 - 19}{2 \cdot 6}

x = \frac{- 23 + 19}{2 \cdot 6} : - \frac{1}{3}

x = \frac{- 23 - 19}{2 \cdot 6} : - \frac{7}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = - \frac{7}{2}

y^{2} - y - 2 y = 0

x, y^{2} - x^{2} + 1 = 50

x, x^{2} + 2 x + 1 = m^{2}

- 3 s^{2} - 12 s - 11 = 0

x^{2} + 36 = - 14 x

What are the solutions to the equation 6x^2+23x=-7 ?
The solutions to the equation 6x^2+23x=-7 are x=-1/3 ,x=-7/2
Find the zeros of 6x^2+23x=-7
The zeros of 6x^2+23x=-7 are x=-1/3 ,x=-7/2