What are the solutions to the equation -3s^2-12s-11=0 ?

The solutions to the equation -3s^2-12s-11=0 are s=-(6+sqrt(3))/3 ,s=-(6-sqrt(3))/3

Find the zeros of -3s^2-12s-11=0

The zeros of -3s^2-12s-11=0 are s=-(6+sqrt(3))/3 ,s=-(6-sqrt(3))/3

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- 3 s^{2} - 12 s - 11 = 0

s = - \frac{6 + 3}{3}, s = - \frac{6 - 3}{3}

Decimal Notation

s = - 2.57735 \dots, s = - 1.42264 \dots

Solution steps

- 3 s^{2} - 12 s - 11 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 ( - 3 ) ( - 11 )}{2 ( - 3 )}

(- 12)^{2} - 4 (- 3) (- 11) = 23

s_{1, 2} = \frac{- ( - 12 ) \pm 2 3}{2 ( - 3 )}

Separate the solutions

s_{1} = \frac{- ( - 12 ) + 2 3}{2 ( - 3 )}, s_{2} = \frac{- ( - 12 ) - 2 3}{2 ( - 3 )}

s = \frac{- ( - 12 ) + 2 3}{2 ( - 3 )} : - \frac{6 + 3}{3}

s = \frac{- ( - 12 ) - 2 3}{2 ( - 3 )} : - \frac{6 - 3}{3}

The solutions to the quadratic equation are:

s = - \frac{6 + 3}{3}, s = - \frac{6 - 3}{3}

x^{2} + 36 = - 14 x

4 y^{2} - 256 = 0

(2 - x) (2 - x) - 1 = 0

x (x + 2) - 2 x (x - 0.5) + 8 = x^{2} - 1

10 x^{2} - 17 x - 3 = 0

What are the solutions to the equation -3s^2-12s-11=0 ?
The solutions to the equation -3s^2-12s-11=0 are s=-(6+sqrt(3))/3 ,s=-(6-sqrt(3))/3
Find the zeros of -3s^2-12s-11=0
The zeros of -3s^2-12s-11=0 are s=-(6+sqrt(3))/3 ,s=-(6-sqrt(3))/3