What are the solutions to the equation 10x^2-17x-3=0 ?

The solutions to the equation 10x^2-17x-3=0 are x=(17+sqrt(409))/(20),x=(17-sqrt(409))/(20)

Find the zeros of 10x^2-17x-3=0

The zeros of 10x^2-17x-3=0 are x=(17+sqrt(409))/(20),x=(17-sqrt(409))/(20)

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10 x^{2} - 17 x - 3 = 0

x = \frac{17 + 409}{20}, x = \frac{17 - 409}{20}

Decimal Notation

x = 1.86118 \dots, x = - 0.16118 \dots

Solution steps

10 x^{2} - 17 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 10 ( - 3 )}{2 \cdot 10}

(- 17)^{2} - 4 \cdot 10 (- 3) = 409

x_{1, 2} = \frac{- ( - 17 ) \pm 409}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 409}{2 \cdot 10}, x_{2} = \frac{- ( - 17 ) - 409}{2 \cdot 10}

x = \frac{- ( - 17 ) + 409}{2 \cdot 10} : \frac{17 + 409}{20}

x = \frac{- ( - 17 ) - 409}{2 \cdot 10} : \frac{17 - 409}{20}

The solutions to the quadratic equation are:

x = \frac{17 + 409}{20}, x = \frac{17 - 409}{20}

9 x^{2} - 16 = 9

0 = 0.05 P - 0.0005 P^{2}

(x)^{2} + (x + 2)^{2} = 724

r^{2} + 10 r - 9 = 0

9 x^{2} - 12 = 0

What are the solutions to the equation 10x^2-17x-3=0 ?
The solutions to the equation 10x^2-17x-3=0 are x=(17+sqrt(409))/(20),x=(17-sqrt(409))/(20)
Find the zeros of 10x^2-17x-3=0
The zeros of 10x^2-17x-3=0 are x=(17+sqrt(409))/(20),x=(17-sqrt(409))/(20)