What are the solutions to the equation 48-48x=(7x+1)(x-1) ?

The solutions to the equation 48-48x=(7x+1)(x-1) are x=1,x=-7

Find the zeros of 48-48x=(7x+1)(x-1)

The zeros of 48-48x=(7x+1)(x-1) are x=1,x=-7

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48 - 48 x = (7 x + 1) (x - 1)

x = 1, x = - 7

Solution steps

48 - 48 x = (7 x + 1) (x - 1)

Expand

(7 x + 1) (x - 1) : 7 x^{2} - 6 x - 1

48 - 48 x = 7 x^{2} - 6 x - 1

Switch sides

7 x^{2} - 6 x - 1 = 48 - 48 x

Move

48 x

to the left side

7 x^{2} + 42 x - 1 = 48

Move

48

to the left side

7 x^{2} + 42 x - 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 42 \pm 4 2 ^{2} - 4 \cdot 7 ( - 49 )}{2 \cdot 7}

4 2^{2} - 4 \cdot 7 (- 49) = 56

x_{1, 2} = \frac{- 42 \pm 56}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 42 + 56}{2 \cdot 7}, x_{2} = \frac{- 42 - 56}{2 \cdot 7}

x = \frac{- 42 + 56}{2 \cdot 7} : 1

x = \frac{- 42 - 56}{2 \cdot 7} : - 7

The solutions to the quadratic equation are:

x = 1, x = - 7

\frac{1}{3} m^{2} + 2 m = 4

4 m (3 m + 2) = m + 12

0 = 3 x^{2} + 12 x - 3

4 (h^{2}) - 64 = 0

2 x^{2} + 8 x = 15

What are the solutions to the equation 48-48x=(7x+1)(x-1) ?
The solutions to the equation 48-48x=(7x+1)(x-1) are x=1,x=-7
Find the zeros of 48-48x=(7x+1)(x-1)
The zeros of 48-48x=(7x+1)(x-1) are x=1,x=-7