What are the solutions to the equation 3(2f-6)^2=108 ?

The solutions to the equation 3(2f-6)^2=108 are f=6,f=0

Find the zeros of 3(2f-6)^2=108

The zeros of 3(2f-6)^2=108 are f=6,f=0

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3 (2 f - 6)^{2} = 108

f = 6, f = 0

Solution steps

3 (2 f - 6)^{2} = 108

Divide both sides by

3

(2 f - 6)^{2} = 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 f - 6 = 36 : f = 6

Solve

2 f - 6 = - 36 : f = 0

The solutions to the quadratic equation are:

f = 6, f = 0

19 y + 5 y^{2} = 30

- 3 + 9 x^{2} = - 20

2 t^{2} - 3 t - 7 = 0

x^{2} + 9 x = - 8

3 x^{1} + 2 x^{2} = 54

What are the solutions to the equation 3(2f-6)^2=108 ?
The solutions to the equation 3(2f-6)^2=108 are f=6,f=0
Find the zeros of 3(2f-6)^2=108
The zeros of 3(2f-6)^2=108 are f=6,f=0