What are the solutions to the equation -3+9x^2=-20 ?

The solutions to the equation -3+9x^2=-20 are x=(sqrt(17))/3 i,x=-(sqrt(17))/3 i

Find the zeros of -3+9x^2=-20

The zeros of -3+9x^2=-20 are x=(sqrt(17))/3 i,x=-(sqrt(17))/3 i

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- 3 + 9 x^{2} = - 20

x = \frac{17}{3} i, x = - \frac{17}{3} i

Solution steps

- 3 + 9 x^{2} = - 20

Move

3

to the right side

9 x^{2} = - 17

Divide both sides by

9

x^{2} = - \frac{17}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{17}{9}, x = - - \frac{17}{9}

- \frac{17}{9} = \frac{17}{3} i

- - \frac{17}{9} = - \frac{17}{3} i

x = \frac{17}{3} i, x = - \frac{17}{3} i

2 t^{2} - 3 t - 7 = 0

x^{2} + 9 x = - 8

3 x^{1} + 2 x^{2} = 54

- 4 + 64 x^{2} = - 3

6 x^{2} - x - 12 = 0

What are the solutions to the equation -3+9x^2=-20 ?
The solutions to the equation -3+9x^2=-20 are x=(sqrt(17))/3 i,x=-(sqrt(17))/3 i
Find the zeros of -3+9x^2=-20
The zeros of -3+9x^2=-20 are x=(sqrt(17))/3 i,x=-(sqrt(17))/3 i