What are the solutions to the equation -4+64x^2=-3 ?

The solutions to the equation -4+64x^2=-3 are x= 1/8 ,x=-1/8

Find the zeros of -4+64x^2=-3

The zeros of -4+64x^2=-3 are x= 1/8 ,x=-1/8

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- 4 + 64 x^{2} = - 3

x = \frac{1}{8}, x = - \frac{1}{8}

Decimal Notation

x = 0.125, x = - 0.125

Solution steps

- 4 + 64 x^{2} = - 3

Move

4

to the right side

64 x^{2} = 1

Divide both sides by

64

x^{2} = \frac{1}{64}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{64}, x = - \frac{1}{64}

\frac{1}{64} = \frac{1}{8}

- \frac{1}{64} = - \frac{1}{8}

x = \frac{1}{8}, x = - \frac{1}{8}

6 x^{2} - x - 12 = 0

201 = 0.1 w^{2} + 2.155 w + 19.985

2 x^{2} - 4 = 5 x

y, y^{2} - x y = 6

x, x - x^{2} - 2 x y = 0

What are the solutions to the equation -4+64x^2=-3 ?
The solutions to the equation -4+64x^2=-3 are x= 1/8 ,x=-1/8
Find the zeros of -4+64x^2=-3
The zeros of -4+64x^2=-3 are x= 1/8 ,x=-1/8