What are the solutions to the equation solvefor x,x-x^2-2xy=0 ?

The solutions to the equation solvefor x,x-x^2-2xy=0 are x=0,x=1-2y

Find the zeros of solvefor x,x-x^2-2xy=0

The zeros of solvefor x,x-x^2-2xy=0 are x=0,x=1-2y

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solve for

x, x - x^{2} - 2 x y = 0

x = 0, x = 1 - 2 y

Solution steps

x - x^{2} - 2 x y = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + (1 - 2 y) x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( 1 - 2 y ) \pm ( 1 - 2 y ) ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

Simplify

(1 - 2 y)^{2} - 4 (- 1) \cdot 0 : - 2 y + 1

x_{1, 2} = \frac{- ( 1 - 2 y ) \pm ( - 2 y + 1 )}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( 1 - 2 y ) - 2 y + 1}{2 ( - 1 )}, x_{2} = \frac{- ( 1 - 2 y ) - ( - 2 y + 1 )}{2 ( - 1 )}

x = \frac{- ( 1 - 2 y ) - 2 y + 1}{2 ( - 1 )} : 0

x = \frac{- ( 1 - 2 y ) - ( - 2 y + 1 )}{2 ( - 1 )} : 1 - 2 y

The solutions to the quadratic equation are:

x = 0, x = 1 - 2 y

- 4 x^{2} + 16 x + 9 = 0

4 x^{2} - 65 x + 16 = 0

x (x + 3) = 70

z^{2} = (1 - i)^{\frac{1}{3}}

2 x (x + 7) = 0

What are the solutions to the equation solvefor x,x-x^2-2xy=0 ?
The solutions to the equation solvefor x,x-x^2-2xy=0 are x=0,x=1-2y
Find the zeros of solvefor x,x-x^2-2xy=0
The zeros of solvefor x,x-x^2-2xy=0 are x=0,x=1-2y