What are the solutions to the equation 28x^2-85x+63=0 ?

The solutions to the equation 28x^2-85x+63=0 are x= 7/4 ,x= 9/7

Find the zeros of 28x^2-85x+63=0

The zeros of 28x^2-85x+63=0 are x= 7/4 ,x= 9/7

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28 x^{2} - 85 x + 63 = 0

x = \frac{7}{4}, x = \frac{9}{7}

Decimal Notation

x = 1.75, x = 1.28571 \dots

Solution steps

28 x^{2} - 85 x + 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 85 ) \pm ( - 85 ) ^{2} - 4 \cdot 28 \cdot 63}{2 \cdot 28}

(- 85)^{2} - 4 \cdot 28 \cdot 63 = 13

x_{1, 2} = \frac{- ( - 85 ) \pm 13}{2 \cdot 28}

Separate the solutions

x_{1} = \frac{- ( - 85 ) + 13}{2 \cdot 28}, x_{2} = \frac{- ( - 85 ) - 13}{2 \cdot 28}

x = \frac{- ( - 85 ) + 13}{2 \cdot 28} : \frac{7}{4}

x = \frac{- ( - 85 ) - 13}{2 \cdot 28} : \frac{9}{7}

The solutions to the quadratic equation are:

x = \frac{7}{4}, x = \frac{9}{7}

v^{2} = - 256

k, (n - k) (- k) = k (n - k)

4 x^{2} - 28 x + 57 = 0

- c^{2} + c + 1 = 0

k^{2} - k = 0

What are the solutions to the equation 28x^2-85x+63=0 ?
The solutions to the equation 28x^2-85x+63=0 are x= 7/4 ,x= 9/7
Find the zeros of 28x^2-85x+63=0
The zeros of 28x^2-85x+63=0 are x= 7/4 ,x= 9/7