What are the solutions to the equation 4x^2-28x+57=0 ?

The solutions to the equation 4x^2-28x+57=0 are x= 7/2+sqrt(2)i,x= 7/2-sqrt(2)i

Find the zeros of 4x^2-28x+57=0

The zeros of 4x^2-28x+57=0 are x= 7/2+sqrt(2)i,x= 7/2-sqrt(2)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} - 28 x + 57 = 0

x = \frac{7}{2} + 2 i, x = \frac{7}{2} - 2 i

Solution steps

4 x^{2} - 28 x + 57 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 4 \cdot 57}{2 \cdot 4}

Simplify

(- 28)^{2} - 4 \cdot 4 \cdot 57 : 82 i

x_{1, 2} = \frac{- ( - 28 ) \pm 8 2 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 28 ) + 8 2 i}{2 \cdot 4}, x_{2} = \frac{- ( - 28 ) - 8 2 i}{2 \cdot 4}

x = \frac{- ( - 28 ) + 8 2 i}{2 \cdot 4} : \frac{7}{2} + 2 i

x = \frac{- ( - 28 ) - 8 2 i}{2 \cdot 4} : \frac{7}{2} - 2 i

The solutions to the quadratic equation are:

x = \frac{7}{2} + 2 i, x = \frac{7}{2} - 2 i

- c^{2} + c + 1 = 0

k^{2} - k = 0

(2 y + 6)^{2} = 36

16 x^{2} + 56 x + 49 = 0

5 x^{2} = 17 x + 40

What are the solutions to the equation 4x^2-28x+57=0 ?
The solutions to the equation 4x^2-28x+57=0 are x= 7/2+sqrt(2)i,x= 7/2-sqrt(2)i
Find the zeros of 4x^2-28x+57=0
The zeros of 4x^2-28x+57=0 are x= 7/2+sqrt(2)i,x= 7/2-sqrt(2)i