What are the solutions to the equation completesquare 2x^2-4x-1=0 ?

The solutions to the equation completesquare 2x^2-4x-1=0 are x=sqrt(3/2)+1,x=-sqrt(3/2)+1

Find the zeros of completesquare 2x^2-4x-1=0

The zeros of completesquare 2x^2-4x-1=0 are x=sqrt(3/2)+1,x=-sqrt(3/2)+1

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2 x^{2} - 4 x - 1 = 0

x = \frac{3}{2} + 1, x = - \frac{3}{2} + 1

Decimal Notation

x = 2.22474 \dots, x = - 0.22474 \dots

Solution steps

2 x^{2} - 4 x - 1 = 0

Move

1

to the right side

2 x^{2} - 4 x = 1

Divide both sides by

2

\frac{2 x ^{2} - 4 x}{2} = \frac{1}{2}

x^{2} - 2 x = \frac{1}{2}

Rewrite in the form

(x + a)^{2} = b

(x - 1)^{2} = \frac{3}{2}

For

the solutions are

f (x) = a, - a

Solve

x - 1 = \frac{3}{2} : x = \frac{3}{2} + 1

Solve

x - 1 = - \frac{3}{2} : x = - \frac{3}{2} + 1

The solutions to the quadratic equation are:

x = \frac{3}{2} + 1, x = - \frac{3}{2} + 1

(x - 13)^{2} = - \frac{1}{3}

3 y - y^{2} + 1 = 0

w (w + 3) = 154

x (x - 1) = x (7 - x)

3 x^{2} + 30 x + 150 = 0

What are the solutions to the equation completesquare 2x^2-4x-1=0 ?
The solutions to the equation completesquare 2x^2-4x-1=0 are x=sqrt(3/2)+1,x=-sqrt(3/2)+1
Find the zeros of completesquare 2x^2-4x-1=0
The zeros of completesquare 2x^2-4x-1=0 are x=sqrt(3/2)+1,x=-sqrt(3/2)+1