What are the solutions to the equation (x-13)^2=-1/3 ?

The solutions to the equation (x-13)^2=-1/3 are x=isqrt(1/3)+13,x=-isqrt(1/3)+13

Find the zeros of (x-13)^2=-1/3

The zeros of (x-13)^2=-1/3 are x=isqrt(1/3)+13,x=-isqrt(1/3)+13

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(x - 13)^{2} = - \frac{1}{3}

x = i \frac{1}{3} + 13, x = - i \frac{1}{3} + 13

Solution steps

(x - 13)^{2} = - \frac{1}{3}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 13 = - \frac{1}{3} : x = i \frac{1}{3} + 13

Solve

x - 13 = - - \frac{1}{3} : x = - i \frac{1}{3} + 13

The solutions to the quadratic equation are:

x = i \frac{1}{3} + 13, x = - i \frac{1}{3} + 13

3 y - y^{2} + 1 = 0

w (w + 3) = 154

x (x - 1) = x (7 - x)

3 x^{2} + 30 x + 150 = 0

3 x^{2} + a x + 12 = 0

What are the solutions to the equation (x-13)^2=-1/3 ?
The solutions to the equation (x-13)^2=-1/3 are x=isqrt(1/3)+13,x=-isqrt(1/3)+13
Find the zeros of (x-13)^2=-1/3
The zeros of (x-13)^2=-1/3 are x=isqrt(1/3)+13,x=-isqrt(1/3)+13