What are the solutions to the equation 3x^2+ax+12=0 ?

The solutions to the equation 3x^2+ax+12=0 are x=(-a+sqrt(a^2-144))/6 ,x=(-a-sqrt(a^2-144))/6

Find the zeros of 3x^2+ax+12=0

The zeros of 3x^2+ax+12=0 are x=(-a+sqrt(a^2-144))/6 ,x=(-a-sqrt(a^2-144))/6

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3 x^{2} + a x + 12 = 0

x = \frac{- a + a ^{2} - 144}{6}, x = \frac{- a - a ^{2} - 144}{6}

Solution steps

3 x^{2} + a x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- a \pm a ^{2} - 4 \cdot 3 \cdot 12}{2 \cdot 3}

Simplify

a^{2} - 4 \cdot 3 \cdot 12 : a^{2} - 144

x_{1, 2} = \frac{- a \pm a ^{2} - 144}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- a + a ^{2} - 144}{2 \cdot 3}, x_{2} = \frac{- a - a ^{2} - 144}{2 \cdot 3}

x = \frac{- a + a ^{2} - 144}{2 \cdot 3} : \frac{- a + a ^{2} - 144}{6}

x = \frac{- a - a ^{2} - 144}{2 \cdot 3} : \frac{- a - a ^{2} - 144}{6}

The solutions to the quadratic equation are:

x = \frac{- a + a ^{2} - 144}{6}, x = \frac{- a - a ^{2} - 144}{6}

5 x^{2} - 10 x + 9 = 0

2 x^{2} - 4 x = 4

6 x^{2} = - 24 x

0 = x^{2} - x - 30

k (k + 5) = 19

What are the solutions to the equation 3x^2+ax+12=0 ?
The solutions to the equation 3x^2+ax+12=0 are x=(-a+sqrt(a^2-144))/6 ,x=(-a-sqrt(a^2-144))/6
Find the zeros of 3x^2+ax+12=0
The zeros of 3x^2+ax+12=0 are x=(-a+sqrt(a^2-144))/6 ,x=(-a-sqrt(a^2-144))/6