What are the solutions to the equation (x-2)(2x+5)=0 ?

The solutions to the equation (x-2)(2x+5)=0 are x=2,x=-5/2

Find the zeros of (x-2)(2x+5)=0

The zeros of (x-2)(2x+5)=0 are x=2,x=-5/2

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(x - 2) (2 x + 5) = 0

x = 2, x = - \frac{5}{2}

Decimal Notation

x = 2, x = - 2.5

Solution steps

(x - 2) (2 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or 2 x + 5 = 0

Solve

x - 2 = 0 : x = 2

Solve

2 x + 5 = 0 : x = - \frac{5}{2}

The solutions to the quadratic equation are:

x = 2, x = - \frac{5}{2}

15 x^{2} + 17 x - 4 = 0

2 x^{2} - 12 x + 1

x^{2} - 24 x - 6 = 0

13 - 13 x = (4 x + 3) (x - 1)

5 x^{2} + 10 x + 78 = 8

What are the solutions to the equation (x-2)(2x+5)=0 ?
The solutions to the equation (x-2)(2x+5)=0 are x=2,x=-5/2
Find the zeros of (x-2)(2x+5)=0
The zeros of (x-2)(2x+5)=0 are x=2,x=-5/2