What are the solutions to the equation u^2+9u+18=0 ?

The solutions to the equation u^2+9u+18=0 are u=-3,u=-6

Find the zeros of u^2+9u+18=0

The zeros of u^2+9u+18=0 are u=-3,u=-6

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u^{2} + 9 u + 18 = 0

u = - 3, u = - 6

Solution steps

u^{2} + 9 u + 18 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 18 = 3

u_{1, 2} = \frac{- 9 \pm 3}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- 9 + 3}{2 \cdot 1}, u_{2} = \frac{- 9 - 3}{2 \cdot 1}

u = \frac{- 9 + 3}{2 \cdot 1} : - 3

u = \frac{- 9 - 3}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

u = - 3, u = - 6

x, f (x^{2}) = x - x^{2}

- (x + 11)^{2} = - 81

2 = 4 x - 6 (x + 1) 4 x - 6 (x + 1)

e x^{2} - x - 2 = 1

3 x^{2} + 9 x + 8 = 0

What are the solutions to the equation u^2+9u+18=0 ?
The solutions to the equation u^2+9u+18=0 are u=-3,u=-6
Find the zeros of u^2+9u+18=0
The zeros of u^2+9u+18=0 are u=-3,u=-6