What are the solutions to the equation ex^2-x-2=1 ?

The solutions to the equation ex^2-x-2=1 are x=(1+sqrt(1+12e))/(2e),x=(1-sqrt(1+12e))/(2e)

Find the zeros of ex^2-x-2=1

The zeros of ex^2-x-2=1 are x=(1+sqrt(1+12e))/(2e),x=(1-sqrt(1+12e))/(2e)

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e x^{2} - x - 2 = 1

x = \frac{1 + 1 + 12 e}{2 e}, x = \frac{1 - 1 + 12 e}{2 e}

Decimal Notation

x = 1.25046 \dots, x = - 0.88258 \dots

Solution steps

e x^{2} - x - 2 = 1

Move

1

to the left side

e x^{2} - x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 e ( - 3 )}{2 e}

(- 1)^{2} - 4 e (- 3) = 1 + 12 e

x_{1, 2} = \frac{- ( - 1 ) \pm 1 + 12 e}{2 e}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1 + 12 e}{2 e}, x_{2} = \frac{- ( - 1 ) - 1 + 12 e}{2 e}

x = \frac{- ( - 1 ) + 1 + 12 e}{2 e} : \frac{1 + 1 + 12 e}{2 e}

x = \frac{- ( - 1 ) - 1 + 12 e}{2 e} : \frac{1 - 1 + 12 e}{2 e}

The solutions to the quadratic equation are:

x = \frac{1 + 1 + 12 e}{2 e}, x = \frac{1 - 1 + 12 e}{2 e}

3 x^{2} + 9 x + 8 = 0

x^{2} + 19 = - 12 x

2 m^{2} + 14 + 8 m = 0

- x^{2} + 9 x - 16 = 0

3 (2 x^{2} + 7) = - 87

What are the solutions to the equation ex^2-x-2=1 ?
The solutions to the equation ex^2-x-2=1 are x=(1+sqrt(1+12e))/(2e),x=(1-sqrt(1+12e))/(2e)
Find the zeros of ex^2-x-2=1
The zeros of ex^2-x-2=1 are x=(1+sqrt(1+12e))/(2e),x=(1-sqrt(1+12e))/(2e)