What are the solutions to the equation -x^2+9x-16=0 ?

The solutions to the equation -x^2+9x-16=0 are x=(9-sqrt(17))/2 ,x=(9+sqrt(17))/2

Find the zeros of -x^2+9x-16=0

The zeros of -x^2+9x-16=0 are x=(9-sqrt(17))/2 ,x=(9+sqrt(17))/2

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- x^{2} + 9 x - 16 = 0

x = \frac{9 - 17}{2}, x = \frac{9 + 17}{2}

Decimal Notation

x = 2.43844 \dots, x = 6.56155 \dots

Solution steps

- x^{2} + 9 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 1 ) ( - 16 )}{2 ( - 1 )}

9^{2} - 4 (- 1) (- 16) = 17

x_{1, 2} = \frac{- 9 \pm 17}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 9 + 17}{2 ( - 1 )}, x_{2} = \frac{- 9 - 17}{2 ( - 1 )}

x = \frac{- 9 + 17}{2 ( - 1 )} : \frac{9 - 17}{2}

x = \frac{- 9 - 17}{2 ( - 1 )} : \frac{9 + 17}{2}

The solutions to the quadratic equation are:

x = \frac{9 - 17}{2}, x = \frac{9 + 17}{2}

3 (2 x^{2} + 7) = - 87

y^{2} - 7 y = 0

d^{2} - 5 d - 14 = 0

x^{2} - 6 x + 16

x^{2} + 6 x - 3

What are the solutions to the equation -x^2+9x-16=0 ?
The solutions to the equation -x^2+9x-16=0 are x=(9-sqrt(17))/2 ,x=(9+sqrt(17))/2
Find the zeros of -x^2+9x-16=0
The zeros of -x^2+9x-16=0 are x=(9-sqrt(17))/2 ,x=(9+sqrt(17))/2