What are the solutions to the equation d^2-5d-14=0 ?

The solutions to the equation d^2-5d-14=0 are d=7,d=-2

Find the zeros of d^2-5d-14=0

The zeros of d^2-5d-14=0 are d=7,d=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

d^{2} - 5 d - 14 = 0

d = 7, d = - 2

Solution steps

d^{2} - 5 d - 14 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 14) = 9

d_{1, 2} = \frac{- ( - 5 ) \pm 9}{2 \cdot 1}

Separate the solutions

d_{1} = \frac{- ( - 5 ) + 9}{2 \cdot 1}, d_{2} = \frac{- ( - 5 ) - 9}{2 \cdot 1}

d = \frac{- ( - 5 ) + 9}{2 \cdot 1} : 7

d = \frac{- ( - 5 ) - 9}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

d = 7, d = - 2

x^{2} - 6 x + 16

x^{2} + 6 x - 3

w^{2} - 14 w + 42 = 0

a^{2} x^{2} + a (b - c) x - b c = 0

0 = 210 + 205.06 t - 4.9 t^{2}

What are the solutions to the equation d^2-5d-14=0 ?
The solutions to the equation d^2-5d-14=0 are d=7,d=-2
Find the zeros of d^2-5d-14=0
The zeros of d^2-5d-14=0 are d=7,d=-2