What are the solutions to the equation w^2-14w+42=0 ?

The solutions to the equation w^2-14w+42=0 are w=7+sqrt(7),w=7-sqrt(7)

Find the zeros of w^2-14w+42=0

The zeros of w^2-14w+42=0 are w=7+sqrt(7),w=7-sqrt(7)

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w^{2} - 14 w + 42 = 0

w = 7 + 7, w = 7 - 7

Decimal Notation

w = 9.64575 \dots, w = 4.35424 \dots

Solution steps

w^{2} - 14 w + 42 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 42}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 42 = 27

w_{1, 2} = \frac{- ( - 14 ) \pm 2 7}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 14 ) + 2 7}{2 \cdot 1}, w_{2} = \frac{- ( - 14 ) - 2 7}{2 \cdot 1}

w = \frac{- ( - 14 ) + 2 7}{2 \cdot 1} : 7 + 7

w = \frac{- ( - 14 ) - 2 7}{2 \cdot 1} : 7 - 7

The solutions to the quadratic equation are:

w = 7 + 7, w = 7 - 7

a^{2} x^{2} + a (b - c) x - b c = 0

0 = 210 + 205.06 t - 4.9 t^{2}

- 60 = 2 (h + 7)^{2} + 4

2 x^{2} - 8 = 10

x^{2} + 6 x = 80

What are the solutions to the equation w^2-14w+42=0 ?
The solutions to the equation w^2-14w+42=0 are w=7+sqrt(7),w=7-sqrt(7)
Find the zeros of w^2-14w+42=0
The zeros of w^2-14w+42=0 are w=7+sqrt(7),w=7-sqrt(7)