What are the solutions to the equation 3x^2-96x+92=0 ?

The solutions to the equation 3x^2-96x+92=0 are x=(2(24+13sqrt(3)))/3 ,x=(2(24-13sqrt(3)))/3

Find the zeros of 3x^2-96x+92=0

The zeros of 3x^2-96x+92=0 are x=(2(24+13sqrt(3)))/3 ,x=(2(24-13sqrt(3)))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - 96 x + 92 = 0

x = \frac{2 ( 24 + 13 3 )}{3}, x = \frac{2 ( 24 - 13 3 )}{3}

Decimal Notation

x = 31.01110 \dots, x = 0.98889 \dots

Solution steps

3 x^{2} - 96 x + 92 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 96 ) \pm ( - 96 ) ^{2} - 4 \cdot 3 \cdot 92}{2 \cdot 3}

(- 96)^{2} - 4 \cdot 3 \cdot 92 = 523

x_{1, 2} = \frac{- ( - 96 ) \pm 52 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 96 ) + 52 3}{2 \cdot 3}, x_{2} = \frac{- ( - 96 ) - 52 3}{2 \cdot 3}

x = \frac{- ( - 96 ) + 52 3}{2 \cdot 3} : \frac{2 ( 24 + 13 3 )}{3}

x = \frac{- ( - 96 ) - 52 3}{2 \cdot 3} : \frac{2 ( 24 - 13 3 )}{3}

The solutions to the quadratic equation are:

x = \frac{2 ( 24 + 13 3 )}{3}, x = \frac{2 ( 24 - 13 3 )}{3}

x (x - 12) + 32 = 0

x, x^{2} - x y + 5 y = 0

x, s (- 1) = x^{2} - 4 x - 21

x^{2} + 10 x + 37 = 0

(x + 7) (x + 2) = 0

What are the solutions to the equation 3x^2-96x+92=0 ?
The solutions to the equation 3x^2-96x+92=0 are x=(2(24+13sqrt(3)))/3 ,x=(2(24-13sqrt(3)))/3
Find the zeros of 3x^2-96x+92=0
The zeros of 3x^2-96x+92=0 are x=(2(24+13sqrt(3)))/3 ,x=(2(24-13sqrt(3)))/3