What are the solutions to the equation solvefor x,s(-1)=x^2-4x-21 ?

The solutions to the equation solvefor x,s(-1)=x^2-4x-21 are x=2+sqrt(-s+25),x=2-sqrt(-s+25)

Find the zeros of solvefor x,s(-1)=x^2-4x-21

The zeros of solvefor x,s(-1)=x^2-4x-21 are x=2+sqrt(-s+25),x=2-sqrt(-s+25)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

x, s (- 1) = x^{2} - 4 x - 21

x = 2 + - s + 25, x = 2 - - s + 25

Solution steps

s (- 1) = x^{2} - 4 x - 21

Expand

s (- 1) : - s

- s = x^{2} - 4 x - 21

Switch sides

x^{2} - 4 x - 21 = - s

Move

s

to the left side

x^{2} - 4 x - 21 + s = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 21 + s )}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot (- 21 + s) : 2 - s + 25

x_{1, 2} = \frac{- ( - 4 ) \pm 2 - s + 25}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 - s + 25}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 - s + 25}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 - s + 25}{2 \cdot 1} : 2 + - s + 25

x = \frac{- ( - 4 ) - 2 - s + 25}{2 \cdot 1} : 2 - - s + 25

The solutions to the quadratic equation are:

x = 2 + - s + 25, x = 2 - - s + 25

x^{2} + 10 x + 37 = 0

(x + 7) (x + 2) = 0

x^{2} = 20 x - 51

x^{2} + 5 x + 2 = 0

x (x + 5)^{2} - x^{3} = 1

What are the solutions to the equation solvefor x,s(-1)=x^2-4x-21 ?
The solutions to the equation solvefor x,s(-1)=x^2-4x-21 are x=2+sqrt(-s+25),x=2-sqrt(-s+25)
Find the zeros of solvefor x,s(-1)=x^2-4x-21
The zeros of solvefor x,s(-1)=x^2-4x-21 are x=2+sqrt(-s+25),x=2-sqrt(-s+25)