What are the solutions to the equation -2x^2=4 ?

The solutions to the equation -2x^2=4 are x=sqrt(2)i,x=-sqrt(2)i

Find the zeros of -2x^2=4

The zeros of -2x^2=4 are x=sqrt(2)i,x=-sqrt(2)i

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- 2 x^{2} = 4

x = 2 i, x = - 2 i

Solution steps

- 2 x^{2} = 4

Divide both sides by

- 2

x^{2} = - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 2, x = - - 2

- 2 = 2 i

- - 2 = - 2 i

x = 2 i, x = - 2 i

x, x^{2} + 2 y - 2 z^{2} = 0

x^{2} - 200 = 0

y, x^{3} = (y - x^{2})^{2}

x^{2} - x = 156

x^{2} + 6 x + 4 x + 24 = 0

What are the solutions to the equation -2x^2=4 ?
The solutions to the equation -2x^2=4 are x=sqrt(2)i,x=-sqrt(2)i
Find the zeros of -2x^2=4
The zeros of -2x^2=4 are x=sqrt(2)i,x=-sqrt(2)i