What are the solutions to the equation (x-2)(x-10)=-16 ?

The solutions to the equation (x-2)(x-10)=-16 are x=6

Find the zeros of (x-2)(x-10)=-16

The zeros of (x-2)(x-10)=-16 are x=6

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(x - 2) (x - 10) = - 16

x = 6

Solution steps

(x - 2) (x - 10) = - 16

Expand

(x - 2) (x - 10) : x^{2} - 12 x + 20

x^{2} - 12 x + 20 = - 16

Move

16

to the left side

x^{2} - 12 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 36 = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 12 )}{2 \cdot 1}

\frac{- ( - 12 )}{2 \cdot 1} = 6

x = 6

The solution to the quadratic equation is:

x = 6

m^{2} - 6 m + 5 = 4 m^{2} - 8

w^{2} + 8 w + 7 = 0

25 x^{2} - 35 x - 30 = 0

(3 x - 2) (7 x - 1) = 0

a^{2} - a = 1

What are the solutions to the equation (x-2)(x-10)=-16 ?
The solutions to the equation (x-2)(x-10)=-16 are x=6
Find the zeros of (x-2)(x-10)=-16
The zeros of (x-2)(x-10)=-16 are x=6