What are the solutions to the equation w(w+4)=-8 ?

The solutions to the equation w(w+4)=-8 are w=-2+2i,w=-2-2i

Find the zeros of w(w+4)=-8

The zeros of w(w+4)=-8 are w=-2+2i,w=-2-2i

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w (w + 4) = - 8

w = - 2 + 2 i, w = - 2 - 2 i

Solution steps

w (w + 4) = - 8

Expand

w (w + 4) : w^{2} + 4 w

w^{2} + 4 w = - 8

Move

8

to the left side

w^{2} + 4 w + 8 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 8 : 4 i

w_{1, 2} = \frac{- 4 \pm 4 i}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- 4 + 4 i}{2 \cdot 1}, w_{2} = \frac{- 4 - 4 i}{2 \cdot 1}

w = \frac{- 4 + 4 i}{2 \cdot 1} : - 2 + 2 i

w = \frac{- 4 - 4 i}{2 \cdot 1} : - 2 - 2 i

The solutions to the quadratic equation are:

w = - 2 + 2 i, w = - 2 - 2 i

(a - 1)^{2} = 5 a

15 x^{2} - 4 = 0

(2 x - 3)^{2} + 7 = 0

x^{2} - 1 = - 3

10 x^{2} - 5 x - 30 = 0

What are the solutions to the equation w(w+4)=-8 ?
The solutions to the equation w(w+4)=-8 are w=-2+2i,w=-2-2i
Find the zeros of w(w+4)=-8
The zeros of w(w+4)=-8 are w=-2+2i,w=-2-2i