What are the solutions to the equation 15x^2-4=0 ?

The solutions to the equation 15x^2-4=0 are x= 2/(sqrt(15)),x=-2/(sqrt(15))

Find the zeros of 15x^2-4=0

The zeros of 15x^2-4=0 are x= 2/(sqrt(15)),x=-2/(sqrt(15))

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15 x^{2} - 4 = 0

x = \frac{2}{15}, x = - \frac{2}{15}

Decimal Notation

x = 0.51639 \dots, x = - 0.51639 \dots

Solution steps

15 x^{2} - 4 = 0

Move

4

to the right side

15 x^{2} = 4

Divide both sides by

15

x^{2} = \frac{4}{15}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{4}{15}, x = - \frac{4}{15}

\frac{4}{15} = \frac{2}{15}

- \frac{4}{15} = - \frac{2}{15}

x = \frac{2}{15}, x = - \frac{2}{15}

(2 x - 3)^{2} + 7 = 0

x^{2} - 1 = - 3

10 x^{2} - 5 x - 30 = 0

0 = 100 + 87 t - 5 t^{2}

x^{2} + 59 = 16 x

What are the solutions to the equation 15x^2-4=0 ?
The solutions to the equation 15x^2-4=0 are x= 2/(sqrt(15)),x=-2/(sqrt(15))
Find the zeros of 15x^2-4=0
The zeros of 15x^2-4=0 are x= 2/(sqrt(15)),x=-2/(sqrt(15))