What are the solutions to the equation x^2+59=16x ?

The solutions to the equation x^2+59=16x are x=8+sqrt(5),x=8-sqrt(5)

Find the zeros of x^2+59=16x

The zeros of x^2+59=16x are x=8+sqrt(5),x=8-sqrt(5)

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x^{2} + 59 = 16 x

x = 8 + 5, x = 8 - 5

Decimal Notation

x = 10.23606 \dots, x = 5.76393 \dots

Solution steps

x^{2} + 59 = 16 x

Move

16 x

to the left side

x^{2} + 59 - 16 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 16 x + 59 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 59}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 59 = 25

x_{1, 2} = \frac{- ( - 16 ) \pm 2 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2 5}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 2 5}{2 \cdot 1}

x = \frac{- ( - 16 ) + 2 5}{2 \cdot 1} : 8 + 5

x = \frac{- ( - 16 ) - 2 5}{2 \cdot 1} : 8 - 5

The solutions to the quadratic equation are:

x = 8 + 5, x = 8 - 5

\frac{( 3 c ^{2} )}{2} = 3 (98)

x^{2} - 7 x + 10 = 3 x - 6

4 x^{2} - 19 x + 21 = 0

2 x^{2} + 8 x - 10 = 0

- 4 = 3 x^{2} - 3 x

What are the solutions to the equation x^2+59=16x ?
The solutions to the equation x^2+59=16x are x=8+sqrt(5),x=8-sqrt(5)
Find the zeros of x^2+59=16x
The zeros of x^2+59=16x are x=8+sqrt(5),x=8-sqrt(5)