What are the solutions to the equation ((3c^2))/2 =3(98) ?

The solutions to the equation ((3c^2))/2 =3(98) are c=14,c=-14

Find the zeros of ((3c^2))/2 =3(98)

The zeros of ((3c^2))/2 =3(98) are c=14,c=-14

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\frac{( 3 c ^{2} )}{2} = 3 (98)

c = 14, c = - 14

Solution steps

\frac{( 3 c ^{2} )}{2} = 3 (98)

Remove parentheses:

(a) = a

\frac{3 c ^{2}}{2} = 3 \cdot 98

Multiply the numbers:

3 \cdot 98 = 294

\frac{3 c ^{2}}{2} = 294

Multiply both sides by

2

3 c^{2} = 588

Divide both sides by

3

c^{2} = 196

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 196, c = - 196

196 = 14

- 196 = - 14

c = 14, c = - 14

x^{2} - 7 x + 10 = 3 x - 6

4 x^{2} - 19 x + 21 = 0

2 x^{2} + 8 x - 10 = 0

- 4 = 3 x^{2} - 3 x

A = x^{2} - 6 x - 16

What are the solutions to the equation ((3c^2))/2 =3(98) ?
The solutions to the equation ((3c^2))/2 =3(98) are c=14,c=-14
Find the zeros of ((3c^2))/2 =3(98)
The zeros of ((3c^2))/2 =3(98) are c=14,c=-14