What are the solutions to the equation 0=6x^2+x-1 ?

The solutions to the equation 0=6x^2+x-1 are x= 1/3 ,x=-1/2

Find the zeros of 0=6x^2+x-1

The zeros of 0=6x^2+x-1 are x= 1/3 ,x=-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = 6 x^{2} + x - 1

x = \frac{1}{3}, x = - \frac{1}{2}

Decimal Notation

x = 0.33333 \dots, x = - 0.5

Solution steps

0 = 6 x^{2} + x - 1

Switch sides

6 x^{2} + x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 6 ( - 1 )}{2 \cdot 6}

1^{2} - 4 \cdot 6 (- 1) = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 \cdot 6}, x_{2} = \frac{- 1 - 5}{2 \cdot 6}

x = \frac{- 1 + 5}{2 \cdot 6} : \frac{1}{3}

x = \frac{- 1 - 5}{2 \cdot 6} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - \frac{1}{2}

2 x^{2} - 3 x - 32 = 0

3 x^{2} = 1 + 6 x

x^{2} + 8 x - 15

3 (x + 2)^{2} - 2 (x - 1) (x + 1) = 11 x + 18

2 x^{2} - 8 x - 5 = 0

What are the solutions to the equation 0=6x^2+x-1 ?
The solutions to the equation 0=6x^2+x-1 are x= 1/3 ,x=-1/2
Find the zeros of 0=6x^2+x-1
The zeros of 0=6x^2+x-1 are x= 1/3 ,x=-1/2