What are the solutions to the equation x^2+8x+16=0 ?

The solutions to the equation x^2+8x+16=0 are x=-4

Find the zeros of x^2+8x+16=0

The zeros of x^2+8x+16=0 are x=-4

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x^{2} + 8 x + 16 = 0

x = - 4

Solution steps

x^{2} + 8 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 16 = 0

x_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 1}

x = \frac{- 8}{2 \cdot 1}

\frac{- 8}{2 \cdot 1} = - 4

x = - 4

The solution to the quadratic equation is:

x = - 4

7 a b^{5} - 56 ab

lo g_{4} (12) - lo g_{4} (3)

f = - 7 (63)

(\frac{3}{4})^{- 1}

0 = 320 - 16 t^{2}

What are the solutions to the equation x^2+8x+16=0 ?
The solutions to the equation x^2+8x+16=0 are x=-4
Find the zeros of x^2+8x+16=0
The zeros of x^2+8x+16=0 are x=-4