What are the solutions to the equation 0=320-16t^2 ?

The solutions to the equation 0=320-16t^2 are t=2sqrt(5),t=-2sqrt(5)

Find the zeros of 0=320-16t^2

The zeros of 0=320-16t^2 are t=2sqrt(5),t=-2sqrt(5)

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0 = 320 - 16 t^{2}

t = 25, t = - 25

Solution steps

0 = 320 - 16 t^{2}

Switch sides

320 - 16 t^{2} = 0

Move

320

to the right side

- 16 t^{2} = - 320

Divide both sides by

- 16

t^{2} = 20

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 20, t = - 20

20 = 25

- 20 = - 25

t = 25, t = - 25

\frac{( 3 ) ^{2} + 4}{( 3 )}

x^{2} + 5 x - 10 = 0

12 x^{2} u + 3 x^{2} v + 28 y u + 7 y v

245 m^{2} n - 210 m n^{2} + 45 n^{3}

- x + 6 > - (2 x + 4)

What are the solutions to the equation 0=320-16t^2 ?
The solutions to the equation 0=320-16t^2 are t=2sqrt(5),t=-2sqrt(5)
Find the zeros of 0=320-16t^2
The zeros of 0=320-16t^2 are t=2sqrt(5),t=-2sqrt(5)